What's weirder is that the bottom two are 6 feef apart
that feef unit is what makes it possible
This actually makes the problem solvable
edit: in 2-D. Even without the typo it was solvable in 3-D.
What dimensional space are the people arranging themselves in?
But seriously, this reminds me of a time at my former (FAANG) employer where HR sent out a 40-minute video about not being an asshole and avoiding lawsuits.
12 minutes or so in, they say "as the number of people in a group increases, the number of potential 1:1 interactions increases exponentially." I thought "actually n(n-1)/2 but whatever", and finished the video intending to get on with my life.
My inbox was FULL of engineers who were irate. "HR have proven themselves to be fools!" "I expect the company to never ask me to waste my time on their bullshit again." "Once again non-technical people talking out their asses."
HR sent a global apology for the error, asked everybody to not watch the video while they fixed it, and released a patched version the next day.
HR should have replied with a "this was a test on how not to be an asshole and you've all failed. You must take the whole training again"
It's a feature not a bug
Sounds like an HR thing to do frfr
It bugs me that people will call anything with a positive second derivative "exponentially increasing". I can do one better: it increases busy-beaver-y! Is that fast enough for people??
I'm a little sad nobody has done the correct math and it's been too long for me to do it off the top of my head lol.
A2+B2=C^2? What distance are the diagonals if the sides are 6' apart?
6x6 + 6x6 = sqrt72 = 8.49' !
I did it bois. Ty calculator for sqrt72...
Now do the conversion factor from feef to feet!
The diagonal is 6ft. The side is 6 ft. So 6² + 6feef² = 6²
1 feef = 0ft
8.49'!~=116699.97'
I am a human, hear me rar.
It is SO HORRIBLE Stephen Hawking got on his feet.
*got on his feef
And out of his grave
It's a tetrahedron, duh
How many dimensions is that picture though?
how much is a "feef"
Let's do the math. Let's name the points A B C D, where A and D are separated by 6 feef, and all other point pairs by 6 feet. There fore, ABC and BCD are equilateral triangles of side length 6 feet. This leaves two possibilities for the distance between A and D: either they are the same point, or their distance is twice the height of an equilateral triangle with 6 feet side. Since A and D are clearly distinct, we'll go with the latter. That makes the distance AD to be equal to 6 feet times the square root of three, giving a value of sqrt(3) feet for one feef.
Thank you, ChatGPT
1 feef is 12 finches
Kid named tetrahedron
The blokes are obviously at different heights, that's all.
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Why? The diagram is from above and they're shifted in 3 dimensions. Now draw that. I'm not asking. DRAW IT!
If the 6 feet is from head to head, couldn't you flip two people upside down?
Ha. I've always imagined it as six horizontal feet. Assume the heads are on the ground orientation agnostic
Simple: they live in doom
I did the math the diagonal distance is ~8.5Ft
I think it's closer to √72 Ft
Idk I just punched it in and rounded
Oh! come on! How hard is it to social distance in a tetrahedron?
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Dang you must be part llama. I don't disagree though. I actually enjoyed not being very close to people bc they be nasty. Even before COVID haha
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No one is mentioning that the math doesn't work out if the staight line distances are constraints then the diagonals are not correct, and vice versa.
i think that is the joke
That's what the whole comment section is discussing. It's the point of the post
Ah, maybe lemmy glitch, post was empty for me when I made the comment
One place where a pyramid scheme would actually work
