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... am I the only one who learned 1+100, 2+99... to make 101 times 50 pairs? Lmao feels like it's much easier. 101 × 50 = 5050
I'd say it's fifty-fifty.
The math is the same, you just wrote it more "casually". For me it was 0+100, 1+99, 2+98 ... 49+51 -> 100 x 50 = 5000, then add the 50 that was missed from the middle for 5050. But yeah I remember coming up with that when I was really young.
This is my first time seeing this problem. Interesting that they taught it in school.
Had a statistics and probability class in hs instead of the standard precalc. I feel it's more applicable for students now than precalc anyways. It felt pretty cool to sit down in class and figure out the odds of winning on a lotto ticket and when the odds indicate you should buy a ticket.
Yeah pre-calc is pretty much remedial math nowadays. You don't even get 100 level math until you're at intermediate algebra!
Thinking of it in terms of statistics makes a lot of sense, I can see how this problem would help develop intuitions.
Sorry if this is stupid but how to deal with sums to odd numbers ? Won't you have a number left over after pairing all the others?
Add the last number onto the end. So the sum of all numbers between 1 and 101 is 50 pairs of 101 plus one extra 101 and the end. It'd end up being 5050 + 101 or 51x101 or 5151